Question

If( a + b) = 16, a^2 + b^2 = 60, then value of ab is ?

Answer 1

i hope this helps you

Answer 2

The value of ab is 98.

Step-by-step explanation:

Given : If (a+b) = 16, $a^2 + b^2 = 60$

To find : The value of ab ?

Solution :

Using algebraic identity,

$(a+b)^2=a^2+b^2+2ab$

We have given,

$(a+b) = 16$ and  $a^2 + b^2 = 60$

Substitute,

$(16)^2=60+2ab$

$256=60+2ab$

$196=2ab$

$ab=\frac{196}{2}$

$ab=98$

Therefore, the value of ab is 98.

#Learn more

Add a^2+2ab+b^2, a^2-2ab+b^2, a^2-ab-b^2

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