Question

If a - b = 16 and a² + b^2 = 400, find ab.​

Answer 1

Given: $a - b = 16 \ and\ a^2+ b^2 = 400$

We have to find the value of$ab$.

As we know that,

$a^{2} +b^{2} =(a-b)^2+2ab$

By using the above concept, we are solving the above equation.

We are solving in the following way:

We have,

$a - b = 16 \ and\ a^2+ b^2 = 400$

Now,

$a^{2} +b^{2} =(a-b)^2+2ab$

$=>400=(16)^2+2ab\\=>400=256+2ab\\=>2ab=400-256\\=>2ab=144\\\\=>ab=\frac{144}{2}\\\\=>ab=72$

Hence, the value of $ab$is$72$.

Answer 2

Answer:

72

Step-by-step explanation:

hope its correct thank you ~♥~