Question

if a+b=17 and ab= 60,find a^2 +b^2 and hence find a- b​

Answer 1

Answer:

Step-by-step explanation:

(a-b)^2=a^2+b^2–2ab

(a+b)^2=a^2+b^2+2ab

given a-b=4 & ab=60

by formula 1 mentioned above

(a-b)^2=a^2+b^2–2ab

4^2=a^2+b^2–2(60)

a^2+b^2=16+120

by formula 2

(a+b)^2=a^2+b^2+2ab

(a+b)^2=a^2+b^2+2ab

(a+b)^2=16+120+2(60)

(a+b)^2=256

a+b=16

Answer 2

Answer:

Given;

a+b = 17 and ab = 60

we have to find a^2+b^2 and a-b

Step-by-step explanation:

We know that (a+b)^2= a2+2ab+b2

(17)^2 = a2+b2+2ab

289=a2+b2+2(60)

289=a2+b2+120

so,a^2+b^2=289-120 = 169

We know that (a-b)^2=a2+b2-2ab

(a-b)^2 = 169-2(60)

so (a-b)2= 169-120= 49

but we have to find a-b

so a-b = √49=7