Question

If a : b= 2:1 and b:c=3:1, then find the value of [a²/6bc)²
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Answer 1

Answer:

The answer is 4/81.

Step-by-step explanation:

Here given, a : b=2:1

b : c = 3:1

∴ a:b:c= 2:3:1

let, a=2x, b=3x, c=x

Now, (a²/6bc)²

=[(2x)²/6·3x·x]²

=(4x²/18x²)²

= (2/9)²  = 4/81

Answer 2

(a²/6bc)² = 4

Explanation:

Given:

1.  a : b = 2:1

2. b : c = 3:1

To find:

(a²/6bc)²

==> a:b =2:1

==> a=2

==> b= 1

==> b:c = 3:1

==>b=3

==>c=1

B is different different

B must be same

a:b =2:1 , b:c = 3:1

b value is 1 and 3

Multiply 3 in a:b

a:b =2(3):1(3)

a: b = 6:3

Multiply 1 in b:c

b:c = 3(1):1(1)

b:c = 3:1

a:b = 6:3

b:c = 3:1

now b is same

a= 6

b=3

c=1

Substitute these values in the given equation

==> (a²/6bc)²

==> (6²/ 6(3)(1))²

==> (36/18)²

==> (6/3)²

==> (2)²

==> 4

(a²/6bc)² =4

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