If (a + b)^2 = 2a^2 + 2b^2
, show that a = b
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Given-
[a+b]^2 = 2a^2 + 2b^2
Then we have to show that a=b
Now as we know that -
[a+b]^2 = a^2 + 2ab + b^2 -------------------- (i)
so, now according to question
[a+b]^2 = 2a^2 + 2b^2 ------------------------ (ii)
using equation (I) and (ii) we get
2a^2 + 2b^2 = a^2 + 2ab + b^2
or, a^2 + b^2 = 2ab
or, a^2 - 2ab + b^2 = 0
or, [a - b]^2 = 0 [using the formula [a-b]^2 = a^2 + 2ab + b^2 ]
so, a - b = 0
Hence a = b proved.
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