if (a+b)²=2a²+2b², show that a=b
Answers
Answered by
0
Answer:
(a+b)²=2a²+2b²
a^2+b^2+2ab=2a^2+2b^2
a^2+b^2-2ab=0
(a-b)^2=0
a-b=0
a=b
hence proved
Answered by
1
Step-by-step explanation:
(a+b)² = 2a²+2b²
=> a²+b²+2ab = 2a²+2b²
=> a²+b²+2ab-2a²-2b² = 0
=> -a²-b²+2ab = 0
=> -(a²+b²-2ab) = 0
=> (a²+b²-2ab) = 0
=> (a-b)² = 0
=> (a-b) = 0
=> a = b (proved)
using formula (x+y)² = x²+y²+2xy
x²+y²-2xy = (x-y)²
Similar questions