Question

if a:b=2:3&p:q=3:2,what the value of (2a²p³+3b²q³):(3abpq²+4a²p²q)​

Answer 1

Step-by-step explanation:

a/b=2/3

a = 2b/3

b = 3a/2

p/q=3/2

p = 3q/2

q = 2p/3

(2a²p³+3b²q³)/(3abpq²+4a²p²q)

=((2(2b/3)²(3q/2)³)+3b²q³)/((3(2b/3)b(3q/2)q²)+(4(2b/3)²(3q/2)²q))

=((2(4b²/9)(27q³/8))+3b²q³)/((3b²q³)+(4(4b²/9)(9q²/4)q))

=(3b²q³+3b²q³)/(3b²q³+4b²q³)

=b²q³(3+3)/b²q³(3+4)

=6/7