Math, asked by TrijitAdhikary5603, 18 days ago

if a:b = 2:3 and a=4, then what is the value of B?

Answers

Answered by avantikaroy978
0

Answer:

b = 6

Step-by-step explanation:

a/ b = 2/3

4/ b = 2/3

12/2 = b

b =6

Attachments:
Answered by payalchatterje
0

Answer:

The value of b is 6.

Step-by-step explanation:

Here given,a:b = 2:3 and a=4

We know,x:y =  \frac{x}{y}

So,

2:3 =  \frac{2}{3}   \\ a:b =  \frac{a}{b}

According to question,

 \frac{a}{b}  =  \frac{2}{3}

By Cross multiplication,

3a = 2b

b =  \frac{3a}{2} ......(1)

It is given that a=4.

We are putting value of a in equation (1),

b =  \frac{3 \times 4}{2}   \\ b = 3 \times 2 \\ b = 6

Required value of b is 6.

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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