Math, asked by thunderstormm0077, 3 days ago

If A:B=2:3 and B:C=4:5 and C:D=1:2 then find the value of 3A+b/2A+D​

Answers

Answered by bson
0

A:B =2:3 = 8: 12

B:C = 4:5 = 12: 15

C:D = 1:2 = 15: 30

A:B:C:D = 8:12:15:30

A=8x => 2A =16x => 3A =24x

B=12x

D=30x

(24x+12x) / (16x+30x)

= 36x / 46x

= 18/23

Answered by reeyantanveer16
0

Answer:

sorry don't know about it.

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