Question

If A:B = 2:3, b:c = 4:5 and C:D = 6:7 Then
Find the Value of A:B:C:D

Please Help me Solve this, With Steps Thank You so much

Answer 1

Hey mate here is your answer

There is a simple way of doing these kind of problems by multiplying both sides with multiples of a number make a paticular variable common in both the ratio

A:B = 1:2 , B:C = 3:4

Now multiply A:B with 3 and multiply B:C with 2

Then A:B = 3:6 and B:C = 6:8

Now combining both A:B:C = 3:6:8

Again C:D = 6:9

Now multiplying A:B:C with 3 and C:D with 4

Then A:B:C = 9:18:24

and C:D = 24:36

Now combining the above two

A:B:C:D = 9:18:24:36

Again D:E = 12:16

Now by multiplying A:B:C:D by 1 and D:E by 3 we get,

A:B:C:D = 9:18:24:36

and D:E = 36:48

So again combining the above two

A:B:C:D:E = 9:18:24:36:48

Since the above ratio is a multiple of 3 so after division:-

A:B:C:D:E = 3:6:8:12:16

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Answer 2

First Finding A:B:C




Given, A : B = 2 : 3 and B : C = 4 : 5


To make B same in both, taking LCM of Bs [ LCM = 12 ]




Hence,

A : B = ( 2 × 4 ) : ( 3 × 4 ) = 8 : 12
B : C = ( 4 × 3 ) : ( 5 × 3 ) = 12 : 15


Due to this, A : B : C = 8 : 12 : 15



Now,



Given, A : B : C = 8 : 12 : 15 and C : D = 6 : 7




To make C same in both, taking LCM of Cs [ LCM = 30 ]


Then,

A : B : C = ( 8 × 2 ) : ( 12 × 2 ) : ( 15 × 2 ) = 16 : 24 : 30

C : D = ( 6 × 5 ) : ( 7 × 5 ) = 30 : 35





Hence,
A : B : C : D = 16 : 24 : 30 : 35
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