Math, asked by tummachaitanya0, 11 months ago

if a: b=2:3,b:c=4:5,c:d= 6:7, find a:b: c: d.plz answer this question fast​

Answers

Answered by gaureshgautam15
1

Answer : Given :. A:B is 2:3

B:C is 4:5

C:D is 6:7

To proof : A:B:C:D

Proof : A:B = 2:3

Let a =2x

b = 3x

B: C = 4:5

Let b = 4x

c = 5x

In in above two ratios,in first B has 3x value and in second B has 4x value. take LCM of 4x and 3X it is 12x.

Tomultiply the value of B in first ratio to 12 xMultiply first ratio with 4x and in other ratio with 3x .

You have ,

A:B = 8x : 12x and B:C = 12x : 15x

On combining these two,

A:B:C = 8x : 12x : 15x Now, C:D is 6:8 C = 6x and D = 8x

now in above two ratios ,in first she has 15 x value and in second c has 6 X value. take LCM of 6x and 15 x.It is 30x

To make the value of C in first ratio to 30x .

Multiply first ratio with 2x and second ratio with 5x .

therefore, A:B:C = 16x : 24x : 30x C:D. = 30x : 40x

On combining these two ,A:B:C:D = 16x : 24x : 30x : 40x If eliminate X ,

we have , A:B:C:D = 16 : 24 : 30 : 40 ...........(1)

you can also divide equation (1) by 2 because 2 is common in this equation .

Hope it is helpful for you .

please mark my answer as brainliest

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