Math, asked by hemamalinilatha, 1 year ago

if a:b=2:3, b:c=6:5 and a+b+c=30 then 2a+3b+4c is


hemamalinilatha: ANY ONE ANSWER FOR THIS QUESTION

Answers

Answered by diya72
4
2a+3b+4c
12+27+60
99
hope u got the ans

hemamalinilatha: NO SIR
diya72: no it is
Answered by DelcieRiveria
10

Answer:

The value of 2a+3b+4c is 92.

Step-by-step explanation:

Given information: a:b=2:3, b:c=6:5.

\frac{a}{b}=\frac{2}{3}

\frac{a}{b}=\frac{2}{3}\times \frac{2}{2}=\frac{4}{6}

\frac{b}{c}=\frac{6}{5}

Now the ratio of a:b:c is 4:6:5.

Let the value of a, b and c are 4x, 6x and 5x respectively.

4x+6x+5x=30

15x=30

x=2

The value of x is 2. So, the value of a, b and c are 8, 12 and 10 respectively.

2a+3b+4c=2(8)+3(12)+4(10)\Rightarrow 16+36+40=92

Therefore the value of 2a+3b+4c is 92.

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