Question

If a:b= 2:3 then find a:b if a:b = (4a+3b/3b )​

Answer 1

Answer:

First we have to substitute values :-

4a+3b/3b = $\sf{ (4×2)+\dfrac{3×3}{3×3}}$

=> $\sf{ (4×2)+\dfrac{(3×3)}{(3×3)}}$

=> $\sf{ 8+\dfrac{9}{9}}$

HERE BOTH 9 ARE IN DIVISION FORM SO THEY WILL BE CANCELLED.

=> $\sf{ \dfrac{9}{9} = \dfrac{1}{1}}$

=> $\sf{ 8+ \dfrac{1}{1}}$

=>8+1

=>9

Answer 2

Answer:

First we have to substitute values :-

4a+3b/3b = \sf{ (4×2)+\dfrac{3×3}{3×3}}(4×2)+

3×3

3×3

=> \sf{ (4×2)+\dfrac{(3×3)}{(3×3)}}(4×2)+

(3×3)

(3×3)

=> \sf{ 8+\dfrac{9}{9}}8+

9

9

HERE BOTH 9 ARE IN DIVISION FORM SO THEY WILL BE CANCELLED.

=> \sf{ \dfrac{9}{9} = \dfrac{1}{1}}

9

9

=

1

1

=> \sf{ 8+ \dfrac{1}{1}}8+

1

1

=>8+1

=>9