If (a+b)2 = 361 and ab=-120 calculate the value of a2+b2
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Answered by
3
we know that
(a+b)^2 = a^2 + 2ab + b^2
thus applying this we get....
361 = a^2 + 2 (-120) + b^2...
361= a^2 + b^2 -240
there fore.....
a^2 + b^2 = 361 + 240
= 601....
(a+b)^2 = a^2 + 2ab + b^2
thus applying this we get....
361 = a^2 + 2 (-120) + b^2...
361= a^2 + b^2 -240
there fore.....
a^2 + b^2 = 361 + 240
= 601....
Answered by
3
Hi...☺
Here is your answer...✌
Given that,
(a + b)² = 361 and ab = -120
Using Identity,
We have,
(a + b)² = a² + b² + 2ab
361 = a² + b² + 2 × (-120)
361 = a² + b² - 240
361 + 240 = a² + b²
=> a² + b² = 601
Here is your answer...✌
Given that,
(a + b)² = 361 and ab = -120
Using Identity,
We have,
(a + b)² = a² + b² + 2ab
361 = a² + b² + 2 × (-120)
361 = a² + b² - 240
361 + 240 = a² + b²
=> a² + b² = 601
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