Math, asked by kashaffatimazeeshan, 6 months ago

If (a + b)2 = = 73 and ab = 65, find the value of a +b.​

Answers

Answered by bhumiarora3
8

Step-by-step explanation:

hey this is ur answer

hope it helps

Attachments:
Answered by Ansh919
0

Answer:

√73

Step-by-step explanation:

because 73 is a prime number, so, can't be defined as x×y.

if x= a+b

and y=a+b

then according to the question,

x×y= (a+b)(a+b) = (a+b)^2 = 73

now this means that (a+b)(a+b) = (√73)(√73)

So, from this we can easily suggest that √73 is equal to a+b.

think, that your question is wrong. value of ab can't be equal to 65.

If you will check the upper solution of bhumiarora (not mine), you will find the value wrong. put that value of a+b in (a+b)^2 and then solve it you will not get 73. But if you will put 73 then it will be 73. So, check your question again please

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