if a-b =2,a^2+b^2=74 find a^3+b^3
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Answer:
±468
Step-by-step explanation:
a-b=2
a²+b²-2ab=4 [squaring both sides]
74-2ab=4 [a²+b²=74;given]
2ab=70
ab=35 → (1)
(a+b)²=a²+b²+2ab
(a+b)²=74+70
(a+b)²=144
(a+b)=±12 → (2) [taking square root of both sides]
a³+b³=(a+b)(a²+b²-ab)
=±12(74-35) [from (1) and (2)]
=±12×39
=±468
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