If a-b=2, a^2+b^2=74, then find a^3+b^3=?
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Answer:
- a-b=2 then (a-b)^2=4
a^2+b^2-2ab=4
2ab=74-4=70
2.(a+b)^2=a^2+b^2+2ab
=74+70
=144
a+b= 12
3.a^3+b^3=(a+b)(a^2+b^2-ab)
=12×(74-35)
=12×39
=468
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