if (a-b)=2 , a^3-b^3 = 26 then (a+b)^2=?
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Answer:
=
Step-by-step explanation:
given (a-b)=2
squaring on both sides
a^2+b^2-2ab=4
a^2+b^2=4+2ab--(1)
(a^3-b^3)=26
(a-b)(a^2+ab+b^2)=26
a^2+ab+b^2=26/2=13
4+3ab=13
3ab=9
ab=3--(2)
(2) substitute in (1)
so
a^2+b^2=4+6=10
but
a+b)^2=a^2+b^2+2ab=10+6=16
a+b=4
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