Question

if (a+b)2 = a2 + 6b + b2, what is the value of a ?

A. 0
B. 1
C. 3
D. 5

Answer 1

Step-by-step explanation:

(a+b)2=2a+6b+2b

(a+b)2=2(a+4b)

a+b=a+4b

a+b-a-4b=0

-3b=0

b=0

then b value sub in eqyation

(a+b)2=2a+6b+2b

(a+0)2=2a+6(0)+2(0)

2a=2a

L.H.S=R.H.S

a=0

then (a,b)=(0,0)

Answer 2

Answer:

$\large\boxed{0}$

Step-by-step explanation:

To find the value of a, first you isolate a on one side of the equation.

Given:

(a+b)=2= a2+6b+b2 (find the value of A)

Solutions:

First, you add numbers from left to right.

Make sure to add similar elements from left to right.

$\displaystyle6b+2b=8b$

$\displaystyle (a+b)*2=2a+8b$

Secondly, expand the form.

$\displaystyle (a+b)*2$

$\large\boxed{\textnormal{DISTRIBUTIVE PROPERTY}}$

$\displaystyle a(b+c)=ab+ac$

A=2

B=A

C=B

$\displaystyle 2a+2b$

Rewrite the problem.

$\displaystyle 2a+2b=2a+8b$

Thirdly, subtract by 2b from both sides.

$\displaystyle 2a+2b-2b=2a+8b-2b$

Solve.

$\displaystyle 8-2=6$

$\displaystyle 2a=2a+6b$

Subtract by 2a from both sides.

$\displaystyle 2a-2a=2a+6b-2a$

Solve.

$\displaystyle 0=6b$

Both sides are equal.

Therefore, the value of (a+b)2=a2+6b+b2 is 0=6b.