If a – b = 2 , ab = 3 . Find a2 + b2 and a3 – b3
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Answered by
0
Answer:
Given:-
a-b=2
ab=3
we know the identity:
(a-b)^2=a^2+b^2-2ab
2^2=a^2+b^2-2*3
a^2+b^2=10
(a-b)^3=a^3-b^3-3ab(a-b)
8=a^3-b^3-3*3*2
a^3-b^3=26
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Answered by
0
Step-by-step explanation:
(a-b) ^2=a^2+b^2+2ab
2^2=a^2+b^2-2×3
4+6=a^2+b^2=10
a^3-b^3=(a-b)(a^2+b^2+ab)
(2)(10+3)=a^3-b^3=26
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