Math, asked by shuklaakshat84, 10 months ago

If (a-b)=2;ab=63 Find a) a2+b2 b) (a+b)2​

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Answered by saurabhsinghbihari
3

Step-by-step explanation:

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Answered by warylucknow
2

(a) The value of (a² + b²) is 130.

(b) The value of (a + b)² is 156.

Step-by-step explanation:

It is provided that:

(a - b) = 2

a × b = 63

(a)

Compute the value of a² + b² as follows:

(a - b)^{2}=a^{2}+b^{2}-2ab\\(2)^{2}=a^{2}+b^{2}-(2\times 63)\\4=a^{2}+b^{2}-126\\a^{2}+b^{2}=130

Thus, the value of (a² + b²) is 130.

(b)

Compute the value of (a + b)² as follows:

(a+b)^{2}=a^{2}+b^{2}+2ab\\=130-(2\times 63)\\=130+126\\=156

Thus, the value of (a + b)² is 156.

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