if (a+b)=2 and ( a-b) =10 , find the value of :( a²+b² ) and find ab
Answers
Answered by
4
The value of. A = 6,
And. B = -4,
Therefore,
(a^2+b^2) = (6^2 + -4^2)
= (12 - 8)
= (4)
HOPE IT WILL BE HELPFUL TO U:-)
richasharma01:
pls correct your answer instead of taking square you multiplied by 2
Answered by
34
another approach
not very different
(a+b)=2,(a-b)=10
(a+b)^2=4
(a-b)^2=100
(a+b)^2+(a-b)^2=2(a^2+b^2)
4+100=2(a^2+b^2)
104=2(a^2+b^2)
a^2+b^2=52
now (a+b)^2-(a-b)^2=4ab
4-100=4ab
-96=4ab
ab=-24
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