if a-b=2 and ab=3, find a³-b³
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Answered by
4
Answer:
we have,
a-b=2. and ab=3
then, a³-b³=?
we know that
(a-b)³= a³-b³-3ab(a-b)
so, a³-b³= (a-b)³+3ab(a-b)
= (2)³+ 3×3×2
= 8+18= 26
Answered by
1
Answer:-
we know that : a³- b³= (a-b)³+3ab(a-b)
put the value of ; a-b =3 and ab = 2
a³-b³= 3³+3 ×2×3
a³-b³= 27 + 18 =45
a³-b³= 45
I hope this helps you.....!!!!!!!!!!
Thanks.....!!!!!!!
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