if (a+b)^2=c^2+ab in a triangle abc and if root 2 sina +cosa=root 3 then the ascending order of the angles a b and c are
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Answered by
0
Answer:
Answer is
shj
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Answered by
1
Answer:
+b
2
+c
2
=ac+ab
3
⇒(
2
3
a
−b)
2
+(
2
a
−c)
2
=0
Therefore,
2
3
a
=b and
2
a
=c
⇒a=
3
/2
b
=
1/2
c
⇒
sin
2
π
a
=
sin
3
π
b
=
sin
6
π
c
Therefore, the given triangle is an right angled.
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