Question

if a + b + 2 C is equals to zero prove that a cube plus b cube plus c square is equals to 6 ABC​

Answer 1

Answer:

proven.

Step-by-step explanation

Use the formula

$x^3 + y^3 + z^3 -3xyz = (x+y+z)(x^2+y^2+z^2 -xy-yz-zx)$.

put x = a , y = b  , z = 2c.

now a+b+2c = 0.     so x+y+z = 0.

So, RHS becomes equal to zero.

thus, $a^3+b^3+(2c)^3 = 3(a)(b)(2c) = 6abc.$

Hence, Proved.

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Answer 2

Answer:

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