If a + b = 2, find the value of a^3 + b^3 +6ab.
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given (a+b) =2
then (a+b)^3 =2^3
a^3+b^3+3a^2b+3ab^2=8
a^3+b^3+3ab(a+b)=8
a^3+b^3+3ab.(2)=8
a^3+b^3+6ab=8 Answer
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