Question

if |a^-b^|=√2.then calculate the value of |a^+√3b^|

Answer 1

Answer:

Explanation:

a = 1

b = 1

Angle = 90°

Cos90° = 0

Answer 2

Answer:

The value of  $|\hat a + \sqrt3 \hat b|$  is equal to  2 .

Explanation:

Given,

            $|\hat a -\hat b| = \sqrt2$  

 →   $\hat a^2 +\hat b^2-2|\hat a||\hat b| \cos\theta = 2$      $[\hat a \ and \ \hat b$   are the unit vectors ]              

    → 1 + 1 - 2 1.1.$cos\theta$  =2            [magnitude of unit vectors is equal to 1]

    → $cos\theta =0$

Now,   $|\hat a + \sqrt3 \hat b|$   $=\sqrt \hat a^2 + 3\hat b^2 +2\sqrt3 |\hat a||\hat b| cos\theta$

                            $= \sqrt{1 +3 + 0$

                            =  $\sqrt{4}$

                             = 2