if a+b =2005 then (-1)^a+(-1)^b=
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Answered by
2
Heya
It's given that a+b=2005
2005 is an odd number.
Only the sum of an even number and odd number gives us an odd number.
That implies, among a and b one is an even number and the other is odd.
(-1) to an even power gives +1
(-1) to an odd power gives -1
+1-1=0
Therefore (-1)^a+(-1)^b=0
Hope it helps!^_^
It's given that a+b=2005
2005 is an odd number.
Only the sum of an even number and odd number gives us an odd number.
That implies, among a and b one is an even number and the other is odd.
(-1) to an even power gives +1
(-1) to an odd power gives -1
+1-1=0
Therefore (-1)^a+(-1)^b=0
Hope it helps!^_^
Answered by
1
Given,
a + b = 2005
We know that 2005 is an odd number,
and the sum of one even and one odd number only can be an odd number.
So, if a is odd then b is even.
= ( -1 )^a + ( -1 )^b
= ( -1 )^odd no. + ( -1 )^even number
= -1 + 1
= 0.
If a is even then b is odd.
= ( -1 )^a + ( -1 )^b
= ( -1 )^even no. + ( -1 )^odd no.
= 1 - 1
= 0.
So, the answer is 0.
a + b = 2005
We know that 2005 is an odd number,
and the sum of one even and one odd number only can be an odd number.
So, if a is odd then b is even.
= ( -1 )^a + ( -1 )^b
= ( -1 )^odd no. + ( -1 )^even number
= -1 + 1
= 0.
If a is even then b is odd.
= ( -1 )^a + ( -1 )^b
= ( -1 )^even no. + ( -1 )^odd no.
= 1 - 1
= 0.
So, the answer is 0.
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