Question

If a+b=21, ab=108, Find a∧2+b∧2.

Answer 1

By using formula,

(a^2+b^2)=a^2+2ab+b^2

By substituting values:

(21)^2=a^2+b^2+2×108

441=a^2+b^2+216

a^2+b^2=441-216

a^2+b^2=225