Question

If a+b=21 ,ab=108 find a square+ b square

Answer 1

Hey!!!!

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We have

=> a + b = 21

and

=> ab = 108

We will use the given part

=> a + b = 21

Square both sides

=> (a + b)² = 441

=> a² + b² + 2ab = 441

Replacing value of ab

=> a² + b² + 2(108) = 441

=> a² + b² = 441 - 216

=> a² + b² = 225

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Hope this helps you

Answer 2

Solution:-

given, a+b= 21 , ab = 108 ,

a^2+b^2 = ?

then ,


${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab \\ {21}^{2} = {a}^{2} + {b}^{2} + 2 \times 108 \\ {a}^{2} + {b}^{2} = 441 - 216 \\ ( {a}^{2} + {b}^{2} = 225)ans$