Math, asked by kamyasukhlani, 4 months ago

If (A + B) = 221, (B + C) = 171 and (A + C)
102, then the value of B is:​

Answers

Answered by dishashivgan123654
0

Answer:

392

Step-by-step explanation:

SOLUTION:

(A+B)=221

(B+C)=171

(A+C)=102

(A+B )+(B+C) + (A+C )= A+B+C

221+171+102= A+B+C

221 +171 +102 =(A+C )+ B

494= 102 + B. (SINCE (A+B)= 102)

494-102= B

392 = B

THEREFORE B=392

HOPE THIS MAY HELP YOU ❣️

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