if,a+b=25,ab=6 find a and b.please do not use trial and error
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it is very simple..
a + b = 25
a = 25 - b ---- equation 1
now a b = 6 substitute the value of a from equation 1 in this equation
(25 - b) b = 6
25 b - b² = 6 take all the terms to RHS
b² -25 b + 6 = 0
this is solved using standard quadratic equation rules.
Δ = 25² - 6*4 = 625 - 24 = 601
b = (25 +- 24.51 ) / 2 = 0.49/2 or 49.51/2
b = 0.245 or 24.755 pair a,b is = 0.245 & 24.755 OR 24.755 & 0.245
a = 24.755 or 0.245
a + b = 25
a = 25 - b ---- equation 1
now a b = 6 substitute the value of a from equation 1 in this equation
(25 - b) b = 6
25 b - b² = 6 take all the terms to RHS
b² -25 b + 6 = 0
this is solved using standard quadratic equation rules.
Δ = 25² - 6*4 = 625 - 24 = 601
b = (25 +- 24.51 ) / 2 = 0.49/2 or 49.51/2
b = 0.245 or 24.755 pair a,b is = 0.245 & 24.755 OR 24.755 & 0.245
a = 24.755 or 0.245
mithravishwa:
sir,b=25 is a wrong answer.the book says its 15 or 10!
u have given a wrong data. give value of a+b and ab again
k sir ur right thanks for the answer
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