If (a + b, 2b + 3c, a - c) =(8, 13, 2),find a, b, c.
Answers
Answered by
1
Answer:
8+5=*₹9&489&3489&36
Step-by-step explanation:
&7%-%*%(%-₹₹=₹+
7₹=4*4)4:48%=4
=3:"7392294*%)(204-%)
Answered by
2
Answer:
a=3
b=5
c=1
Step-by-step explanation:
Given: a+b=8
2b+3c=13
a-c=2
To find: values of a, b and c
Solution:
a+b=8
a=8-b EQ.A
a-c=2
a=2+c EQ.B
RHS ARE EQUAL SO THE LHS ARE EQUAL TOO
∴8-b = 2+c
c+b=6 [ MULTIPLY BY 2(SO THAT B GETS CANCELED IN FUTURE STEPS) ]
2c+2b=12 EQ.1
2B+3C=13 EQ.2 [given]
EQ.2 subtracted from EQ.1 we get
C=1 (substitute in EQ.B)
a=c+2
a=1+2
a=3(substitute in EQ.A)
a=8-b
3=8-b
b=8-3
b=5
HENCE FOUND THE VALUES OF a, b AND c.
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