Math, asked by nikhils8044, 5 months ago

If (a + b, 2b + 3c, a - c) =(8, 13, 2),find a, b, c.​

Answers

Answered by lakshmangowdasr22
1

Answer:

8+5=*₹9&489&3489&36

Step-by-step explanation:

&7%-%*%(%-₹₹=₹+

7₹=4*4)4:48%=4

=3:"7392294*%)(204-%)

Answered by niranjnasp
2

Answer:

a=3

b=5

c=1

Step-by-step explanation:

Given: a+b=8

2b+3c=13

a-c=2

To find: values of a, b and c

Solution:

a+b=8

a=8-b                  EQ.A

a-c=2

a=2+c                  EQ.B

RHS ARE EQUAL SO THE LHS ARE EQUAL TOO

∴8-b = 2+c

c+b=6 [ MULTIPLY BY 2(SO THAT B GETS CANCELED IN FUTURE STEPS) ]

2c+2b=12             EQ.1

2B+3C=13            EQ.2 [given]

EQ.2 subtracted from EQ.1 we get

C=1 (substitute in EQ.B)

a=c+2

a=1+2

a=3(substitute in EQ.A)

a=8-b

3=8-b

b=8-3

b=5

HENCE FOUND THE VALUES OF a, b AND c.

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