Question

if (a + b 2b + 3c, a-c) - (8, 13, 2), find a, b, c.​

Answer 1

Answer:

a+b=-8->1 , 2b+3c=-13->2 ,a-c=-2->3

a+b=-8

a=-8-b

apply a in 3

-8-b-c=-2

-b-c=-2+8

-b-c=6->4

use elimination in 2eq and 4eq and also mul 4eq by 2

2b/+3c=-13 (/ means cancelling)

-2b/-2c=6

________

c=-7

apply c in 3 eq and 2eq

a-(-7)=-2 2b+3(-7)= -13

a+7=-2 2b-27= -13

a=-2-7 2b= -13+27

a=-9 2b= 14

b=7

:. a= -9,b=7,c= -7

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Answer 2

Answer:

a=3

b=5

c=1

Step-by-step explanation:

Given: a+b=8

2b+3c=13

a-c=2

To find: values of a, b and c

Solution:

a+b=8

a=8-b                  EQ.A

a-c=2

a=2+c                  EQ.B

RHS ARE EQUAL SO THE LHS ARE EQUAL TOO

∴8-b = 2+c

c+b=6 [ MULTIPLY BY 2(SO THAT B GETS CANCELED IN FUTURE STEPS) ]

2c+2b=12             EQ.1

2B+3C=13            EQ.2 [given]

EQ.2 subtracted from EQ.1 we get

C=1 (substitute in EQ.B)

a=c+2

a=1+2

a=3(substitute in EQ.A)

a=8-b

3=8-b

b=8-3

b=5

HENCE FOUND THE VALUES OF a, b AND c.