if a+b=2b and 1/b+1/d=2c then p.t. a:b::c:a
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Answer:
=> a/b = c/d
Step-by-step explanation:
Given,
=> a + c = 2b
=> a = 2b - c ---------- ( 1 )
And,
=> ( 1/b ) + ( 1/d) = 2/c
Taking L.C.M of b and d.
=> ( d + b )/bd = 2/c
=> ( b + d ) = 2bd/c
=> b = ( 2bd / c ) - d
=> b = ( 2bd - dc )/c
Taking out d as common,
=> b = d ( 2b - c )/ c -------- ( 2 )
Now, by divding ( 1 ) by ( 2 ),
=> a/b = ( 2b - c ) ÷ { d( 2b - c ) /c }
=> a/b = { ( 2b - c ) × c } ÷ { d ( 2b - c ) }
=> a/b = c/d
★ Proved ★
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