Math, asked by is875130, 5 months ago

If a+b+2c= 0, prove that a³+b³+8c³=6abc

Answers

Answered by hakimsarah75

4

Step-by-step explanation:

(a+b+2c)^3=a³+b³+8c³+6abc(a+b+2c)

(0)^3=a³+b³+8c³+0

6abc=a³+b³+8c³

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