Question

If a + b + 2c = 0, prove that a3 + b3 + 8c3=6abc
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Answer 1

Step-by-step explanation:

a+b+2c=0

a+b= - 2c

cubing on both sides

(a+b)³=(-2c)³

a³+b³+3ab(a+b)= - 8c³

a³+b³+3ab(-2c)= - 8c³

a³+b³-6abc = -8c³

a³+b³+8c³=6abc (proved)

Answer 2

Step-by-step explanation:

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