Question

If a+b+2c=0,then prove that a^3+b^3+8c^3=6abc​

Answer 1

Answer & Step-by-step explanation:

Given,

= a+b+2c = 0

= a+b = -2c

By cubing both sides, we get,

= (a+b)³ = (-2c)³

= a³+b³+3ab(a+b) = -8c³

= a³+b³+3ab*(-2c) = -8c³

= a³+b³-6abc = -8c³

= a³+b³+8c³ = 6abc

Hence, Proved.

Hope this helps.

Answer 2

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