if a+b=2c then find (a/(a-c))+(c/(b-c))
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Answered by
5
a+b=2c
or,a+b=c+c
or,a-c=c-b
Now (a/(a-c))+(c/(b-c))
=(a/(a-c))-(c/(c-b))
=(a/(a-c))-(c/(a-c)) [a-c=c-b]
=a-c/a-c
=1
or,a+b=c+c
or,a-c=c-b
Now (a/(a-c))+(c/(b-c))
=(a/(a-c))-(c/(c-b))
=(a/(a-c))-(c/(a-c)) [a-c=c-b]
=a-c/a-c
=1
Answered by
0
Answer:
Step-by-step explanation:
Put C= 0
Then ans is 1
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