Question

If a = b^2x, b = c^2y and a^2z, prove that xyz = 1/8.

Answer 1

Answer:

Step-by-step explanations

a = b^2x

a = (c^2y)^2x

a = {(a^2z)^2y}^2x

a = a^8xyz

comparing powers on both sides…

1 = 8xyz

=>xyz = 1÷8

thus, LHS = RHS

hence proved.

mark as brainliast if it helped.

Answer 2

a = b^2x

a = (c^2y)^2x

a = {(a^2z)^2y}^2x

a = a^8xyz

Comparing.

1 = 8xyz

=> xyz =1/8

thus, LHS = RHS

hence proved.