If,
a= b^2x
b= c^2y
c= a^2x
Prove that
xyz= 1/8
Answers
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Answer:
a = b^2x
a = (c^2y)^2x
a = {(a^2z)^2y}^2x
a = a^8xyz
comparing powers on both sides…
1 = 8xyz
=>xyz = 1÷8
thus, LHS = RHS
hence proved.
Step-by-step explanation:
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