if a=b^2x,b=c^2y,c=a^2z,prove that xyz=1÷8
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Answered by
82
a = b^2x
a = (c^2y)^2x
a = {(a^2z)^2y}^2x
a = a^8xyz
comparing powers on both sides…
1 = 8xyz
=>xyz = 1÷8
thus, LHS = RHS
hence proved.
mark as brainliast if it helped.
a = (c^2y)^2x
a = {(a^2z)^2y}^2x
a = a^8xyz
comparing powers on both sides…
1 = 8xyz
=>xyz = 1÷8
thus, LHS = RHS
hence proved.
mark as brainliast if it helped.
Answered by
3
Step-by-step explanation?
xyz=1/8
hence LHS=RHS
PROVED
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