Question

If a:b = 3:1 and b:c = 5:1 then find the value of a²/7bc

Answer 1

Answer:

$\frac{45}{7}$

Step-by-step explanation:

As per the question,

We have been provided that,

a:b = 3:1   and b:c = 5:1 which can be written as

$\frac{a}{b}=\frac{3}{1}$

⇒ a= 3b

$\frac{b}{c}=\frac{5}{1}$

⇒ b = 5c

Now,

$\frac{a^{2}}{7bc}$

put the values of a and b, we get

$\frac{(3b)^{2}}{7(5c)c}$

$\frac{9b^{2}}{35c^{2}}$

On further solving, we get

$\frac{9}{35} \times (\frac{b}{c})^{2}$

$\frac{45}{7}$

Hence, the required value of $\frac{a^{2}}{7bc}$ = $\frac{45}{7}$.