Question

IF A+B=3π/4, (1-TAN A) (1- TAN B)

Answer 1

Answer:

Step-by-step explanation:

Tan(A-B)=Tan(3pi/4)

TanA-TanB/1+TanA×TanV=Tan(pi-pi/4)

TanA-TanB/1+TanA×TanB=-Tanpi/4

TanA-TanB=-1TanA×TanB

TanA-TanB+TanA×TanB=-1......(1)

Now (1-TanA)(1+TanB)

1+TanB-TanA-TanA×TanB

1-TanA-TanB+TanA×TanB

From(1)

1-(-1)=1+1=2

There Fore (1-TanA)(1+TanB)=2

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