Question

if A:B=3:4 and B:C=6:5,then what is A :(B+C)​

Answer 1

Step-by-step explanation:

A:B=3:4=9:12

B:C=6:5=12:10

So, A:B:C=9:12:10.

Let, A,B,C = 9K,12K,10K.

So, A:(B+C)= 9K:(12K+10K)

= 9K:22K

= 9:22 [Ans]

Answer 2

Solution →

Given that :-

A:B = 3:4

B:C = 6:5

To find :-

A : ( B + C)

So, according to the question .

$= > \frac{a}{b} = \frac{3}{4}$

Multiplying and dividing by 3

$= > \frac{a}{b} = \frac{9}{12}$

$\frac{b}{c} = \frac{6}{5}$

Multiplying and dividing by 2

$= > \frac{12}{10} = \frac{b}{c}$

So from here we got new ratios of A: B : c = 9: 12 : 10

So A = 9 ; B = 12 ; C = 10

A : ( B+C) = 9 : ( 12 +10)

=> 9 : 22

So, the required Ratio is 9 : 22 .