If a/b =3/4 find the value of ratio 3a+b/ 3a-b
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So A:B has a ratio of 3:4; that is, A is three fourths of four.
Thus, you could reduce the values of A and B such that A = 3 and B = 4
Example:
A:B = 9/12
A:B = 34
A:B = 150/200
A:B = 3/4
So we substitute 3 for A and 4 for B in the second algebraic expression in your question:
(3A^2 + 4B)/(3A-4B^2)
I’m assuming this is what you meant to write, and will attempt to simplify this:
(3*3^2 + 4*4) / (3*3–4*4^2)
First, raise the exponents, then do the multiplication, then the addition and subtraction, and then divide in the middle:
(3*9+16)/(9–16)
(27+16)/(9–16)
(43)/(-7)
-43/7
Step-by-step explanation:
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