Math, asked by sobhapal90, 9 months ago

If a:b =3:5, b:c= 7:9 .find a:b:c?​

Answers

Answered by amitpatel17
2

Step-by-step explanation:

the correct answer is 21:35:45

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Answered by Anonymous
2

a:b:c = 21:35:45

Step-by-step explanation:

Given,

a:b =3:5, b:c= 7:9

Given that a:b=5:9 and b:c=4:7.

Here the common term is b which is found in both the ratios.

Ok now let’s look at the value of b in 1st ratio. It is 5. And 7 in the second.

Now we have to take the LCM of these two values so that we are changing the value of b into the LCM value in both the ratios. The LCM is 35.

So we change the value of b into 35 in the 1st and 2nd ratio. 5×7=35. So multiply the whole 1st ratio by 7 making a:b= 21:35

Similarly change the value of b as 35 in the second ratio. 7×5=36. Hence multiply the entire second ratio by 5 making b:c=35:45

Now that the value of b in both the ratio being same we can concatenate them. Hence a:b:c=21:35:45

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