If a/b = -3/7^9 ÷ -3/7^8, the value of (a/b)^3 is
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We have (a+b)3=a3+b3+3ab(a+b)
∴a3+b3=(a+b)3−3ab(a+b)
=(9)3−3×20(9)
=729−540=189
∴a3+b3=189
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