Question

if a-b=3 a^2+b^2=29 then what is the value of ab(show steps) pls dont write if you dont know the answers

Answer 1

Answer:

ab=10

Step-by-step explanation:

given that a-b=3

squaring both side

(a-b)^2=3^2. (open the identity a^2+b^2-2ab)

a^2+b^2-2ab=9

29-2ab=9. (here put the value of a^2+b^2)

-2ab=9-29

-2ab= -20

ab=10

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