If ∣∣∣A→×B→∣∣∣=3–√A→ .B→ then the value of ∣∣∣A→+B→∣∣∣ is
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If ∣∣∣A→×B→∣∣∣=3–√A→ .B→ then the value of ∣∣∣A→+B→∣∣∣ is
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Answer:It's trueStep-by-step explanation:|a vector+b vector|=a^2+b^2+2ab cos thetaif we subtract it,we get a^2+b^2+2ab cos(180°- theta)if these are ... More
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